Asked by MLB
A)If a freight train can accelerate at 0.050 m/sec^2, how far must it travel to increase its speed from 2.0 to 8.0 m/sec? B) how long will it take the train to accomplish this?
Answers
Answered by
Henry
A. Vf^2 = Vo^2 + 2ad = 8^2.
2^2 + 2 * 0.05 * d = 64,
4 + 0.1d = 64,
0.1d = 64 - 4 = 60,
d = 60 / 0.1 = 600m.
B. Vf = Vo + at = 8m/s.
2 + 0.05t = 8,
0.05t = 8 - 2 = 6,
t = 6 / 0.05 = 120s.
2^2 + 2 * 0.05 * d = 64,
4 + 0.1d = 64,
0.1d = 64 - 4 = 60,
d = 60 / 0.1 = 600m.
B. Vf = Vo + at = 8m/s.
2 + 0.05t = 8,
0.05t = 8 - 2 = 6,
t = 6 / 0.05 = 120s.
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