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50.0 mL of 0.200 M NaOH neutralized 20.0 mL of sulfuric acid. Determine the

concentration of the acid. Show a balanced chemical equation, all work, and the answer
rounded to three decimal places.

2 answers

2NaOH + H2SO4 ==> Na2SO4 + 2H2O
mols NaOH = M x L = approx 0.01
mols H2SO4 = 1/2 that from the coefficients in the balanced equation.
M H2SO4 = mols H2SO4/L H2SO4 = ?
0.250M
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