moles NaOH = M x L = ??
IF (and that's a big if) moles acid = moles NaOH, then concn acid = mole/0.120 L. I don't think you have enough information to calculate Ka and pKa of the weak acid. Is the 1 g pure acid or is it a sample mixture? Does part B go with part A using the same data? I don't get part B at all
Part A:
Unknown Acid use 1gram and mix with 120 mL of distilled water
Determine the concentration of the acid by titrating with 0.0998 M of NaOH
Concentration of NaOH= 0.0998M
Volume of NaOH= 3.5 mL
# moles of NaOH=
Initial Concentration of Weak Acid-
Show Calculation of Ka and pKa of weak acid:
Part B:
pH of solution – 3.22 ( determined by using a pH meter to find pH of weak acid)
Show calculation of Ka and pKa of weak acid
2 answers
Yes they go together