5 liters of Butane gas (C4H10) is reacted with plenty of oxygen at 27 oC and 1 atm to produce carbon dioxide and water vapor. Calculate the following:

Question

1- The volume of CO2 produced at 1 atm and 400 oC.

2- The mass of H2O vapor produced.

3- The mol % of the products.

Given:

C4H10 + O2 = CO2 + H2O (Unbalanced equation)

Answer 1

balance the equation.

calculate the moles of butane ( PV=nRT) you started with.

Use the mole ratio in the balanced equation to tell you how many moles of product you get,
then convert (PV=nRT) from moles to volume.

I will be happy to critique your work.