How many miles of vapor are formed when 10 liters of butane gas, C4H10 is burned in oxygen at STP?

Answer 1

Can't answer with just one dimension of miles. Perhaps you meant "moles"..
2C4H10 + 13O2 ==> 8CO2 + 10H2O
10 L C4H10 will give you 40 L CO2 vapor and 50 L H2O vapor.or a total of 90 L gas @ STP. 1 mol occupies 22.4L so convert 90 L to mols with the factory of 22.4 L.

Answer 2

2C4H10 +13H2O=8Co2 +10H2O
10\44.8=X\10
X=10×10\44.8
X=100\44.8
X=2.23

Answer 3

2C4H10 +13H2O=8Co2 +10H2O
10\44.8=X\10
X=10×10\44.8
X=100\44.8
X=2.23
i.e If the mile is mole