∫^5 2 (3x−8)^4dx= ∫^b a f(u)du

Question

du=
(enter a function of x)

Answer 1

clarify your question

to type a power, we use this notation :
4^3
means you have a base of 4 to the exponent 3
your ∫^5 2 is meaningless as is the first part of ∫^b a f(u)du

so again:
base first, then ^ to show exponent, then the exponent
e.g. x^2 for "x squared"

Answer 2

Let u = 3x-8, du = 3dx
∫[2,5] (3x−8)^4 dx = ∫[-2,7] 1/3 u^4 du

Answer 3

oobleck , that makes sense.
Did not see that they wanted the definite integral and the 5 and 2 are the
upper and lower values.