To calculate how much ice is melted when 5,000 Joules of heat is added, we can use the formula for heat transfer during phase change:
\[ Q = m \cdot L_f \]
Where:
- \(Q\) is the heat added (in Joules),
- \(m\) is the mass of the ice melted (in kg),
- \(L_f\) is the heat of fusion of water (in J/kg).
Given:
- \(Q = 5000 , \text{J}\)
- \(L_f = 3.34 \times 10^5 , \text{J/kg}\)
We can rearrange the formula to solve for \(m\):
\[ m = \frac{Q}{L_f} \]
Substituting in the values:
\[ m = \frac{5000 , \text{J}}{3.34 \times 10^5 , \text{J/kg}} \]
Calculating \(m\):
\[ m = \frac{5000}{334000} \approx 0.01497 , \text{kg} \]
Thus, the mass of ice melted is approximately \(0.01497 , \text{kg}\) or \(14.97 , \text{grams}\).
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