Question
What amount of heat is required to increase the temperature of 75.0 grams of gold from 150°C to 250°C? The specific heat of gold is 0.13 J/g°C.
A.
750 joules
B.
980 joules
C.
1300 joules
D.
1500 joules
E.
2500 joules
A.
750 joules
B.
980 joules
C.
1300 joules
D.
1500 joules
E.
2500 joules
Answers
GPT-4o mini
To find the amount of heat required to increase the temperature of gold, we can use the formula:
\[ Q = mc\Delta T \]
where:
- \( Q \) is the heat absorbed or released (in joules),
- \( m \) is the mass (in grams),
- \( c \) is the specific heat capacity (in J/g°C),
- \( \Delta T \) is the change in temperature (in °C).
Given:
- \( m = 75.0 \) grams,
- \( c = 0.13 \) J/g°C,
- Initial temperature \( T_i = 150°C \),
- Final temperature \( T_f = 250°C \).
First, we calculate the change in temperature:
\[ \Delta T = T_f - T_i = 250°C - 150°C = 100°C \]
Now we can substitute the values into the equation:
\[ Q = (75.0 \, \text{g}) \times (0.13 \, \text{J/g°C}) \times (100 \, \text{°C}) \]
Calculating \( Q \):
\[ Q = 75.0 \times 0.13 \times 100 \]
\[ Q = 75.0 \times 13 \]
\[ Q = 975 \, \text{J} \]
Since none of the options exactly match our calculation, but 980 joules (option B) is the closest.
Therefore, the answer is:
**B. 980 joules**.
\[ Q = mc\Delta T \]
where:
- \( Q \) is the heat absorbed or released (in joules),
- \( m \) is the mass (in grams),
- \( c \) is the specific heat capacity (in J/g°C),
- \( \Delta T \) is the change in temperature (in °C).
Given:
- \( m = 75.0 \) grams,
- \( c = 0.13 \) J/g°C,
- Initial temperature \( T_i = 150°C \),
- Final temperature \( T_f = 250°C \).
First, we calculate the change in temperature:
\[ \Delta T = T_f - T_i = 250°C - 150°C = 100°C \]
Now we can substitute the values into the equation:
\[ Q = (75.0 \, \text{g}) \times (0.13 \, \text{J/g°C}) \times (100 \, \text{°C}) \]
Calculating \( Q \):
\[ Q = 75.0 \times 0.13 \times 100 \]
\[ Q = 75.0 \times 13 \]
\[ Q = 975 \, \text{J} \]
Since none of the options exactly match our calculation, but 980 joules (option B) is the closest.
Therefore, the answer is:
**B. 980 joules**.