4y+1=

1 answer

The equation \( 4y + 1 = 0 \) can be solved for \( y \).

To isolate \( y \), follow these steps:

  1. Subtract 1 from both sides: \[ 4y + 1 - 1 = 0 - 1 \] This simplifies to: \[ 4y = -1 \]

  2. Divide both sides by 4: \[ y = \frac{-1}{4} \]

So, the solution for \( y \) is: \[ y = -\frac{1}{4} \]

If you have a different intention for the equation (like perhaps equating it to another value), please provide more context!