To solve this system of equations, we can use the method of substitution.
First, let's solve the second equation for x:
x - 5y = -20
x = 5y - 20
Now substitute x = 5y - 20 into the first equation:
-4(5y - 20) + 6y = 38
-20y + 80 + 6y = 38
-14y + 80 = 38
-14y = -42
y = 3
Now substitute y = 3 into x = 5y - 20:
x = 5(3) - 20
x = 15 - 20
x = -5
Therefore, the solution to the system of equations is x = -5 and y = 3.
-4x+6y=38
X-5y=-20
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