mols Fe ==> grams/molar mass = ?
Convert to mols O2. That's ?mols Fe x (3 mols O2/4 mols Fe) = ?
Then mols O2 x 22.4 L/mol = L O2
4Fe + 3O2 = 2Fe2O3
158g of Fe will react with how many litres of O2 to produce the maximum amount of Fe2O3
1 answer