Asked by Sara
I wrote the dissociation or ionization in water for each of the following acids. I just want someone to check if they are right.
a) HC3H5O2(aq)<===> H^+(aq)+ C3H5O2^-(aq)
b) (CH3)2NH2^+(aq)<===> H^+(aq)+ (CH3)2NH(aq)
c) CH3COOH(aq)<===> H^+(aq)+ CH2COOH^-(aq)
d) H2PO4^-(aq)<===> H^+(aq)+ HPO4^2-
e) [Mn(H2O)6]^2+ <===> I don't know what to do with this one
Thanks
a) HC3H5O2(aq)<===> H^+(aq)+ C3H5O2^-(aq)
b) (CH3)2NH2^+(aq)<===> H^+(aq)+ (CH3)2NH(aq)
c) CH3COOH(aq)<===> H^+(aq)+ CH2COOH^-(aq)
d) H2PO4^-(aq)<===> H^+(aq)+ HPO4^2-
e) [Mn(H2O)6]^2+ <===> I don't know what to do with this one
Thanks
Answers
Answered by
Sara
e) [Mn(H2O)6]^2+(aq)<===> H^+(aq)+ [Mn(H2O)5]5OH^+(aq)
Answered by
Dr Russ
a) HC3H5O2(aq)<===> H^+(aq)+ C3H5O2^-(aq)
This is an odd way to write the this
a) C3H5O2H(aq)<===> H^+(aq)+ C3H5O2^-(aq)
Your answer to a) means you have shown the wrong proton dissociating here.
c) CH3COOH(aq)<===> H^+(aq)+ CH2COOH^-(aq)
should be
c) CH3COOH(aq)<===> H^+(aq)+ CH3COO^-(aq)
[It is possible to remove the proton that you have shown but not in water]
I am not clear what they are after for e) either.
They may be simple be looking for
e) [Mn(H2O)6]^2+H2O<===> H^+(aq)+ [Mn(H2O)6]OH^+(aq)
This is an odd way to write the this
a) C3H5O2H(aq)<===> H^+(aq)+ C3H5O2^-(aq)
Your answer to a) means you have shown the wrong proton dissociating here.
c) CH3COOH(aq)<===> H^+(aq)+ CH2COOH^-(aq)
should be
c) CH3COOH(aq)<===> H^+(aq)+ CH3COO^-(aq)
[It is possible to remove the proton that you have shown but not in water]
I am not clear what they are after for e) either.
They may be simple be looking for
e) [Mn(H2O)6]^2+H2O<===> H^+(aq)+ [Mn(H2O)6]OH^+(aq)
Answered by
Sara
Thanks, that helped a lot
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.