Question

For the dissociation of acetic acid, CH3COOH CH3COO- + H+, the free energy change, ΔG° = 27.26 kJ/mol. What is the free energy change, ΔG°', in the biochemical standard state? Given R = 8.315 J/mol · K. T = 25°C.

Answer 1

I'm not a biochemistry and have never worked with dGo' but it appears to me from reading that dGo' = dGo + RTln[(H^+)/(H2O)] and since H^+ = 10^-7 and (H2O) = 55.5 you calculate that part of it and add to dGo to solve for dGo'.