Asked by JayCee
a block of mass 2.50 kg rests on a ramp. if the coefficient of static friction between the block and ramp is 0.350, what maximum angle can the ramp make with the horizontal before the block starts to slip down?
Answers
Answered by
Henry
F = 2.50 * 9.8 = 24.5N @ A deg.
Fp = 24.5*sinA = Force parallel with plane.
Fv = 24.5*cosA = Force perpendicular to
plane.
uFv = 0.35Fv = Force of friction.
Fp - 0.35Fv = ma,
a = 0(block at rest),
Fp -0.35Fv = 0,
Fp = 0.35Fv,
24.5*sinA = 0.35*24.5*cosA,
Divide both sides by 24.5:
sinA = 0.35*cosA
Divide both sides by cosA:
sinA / cosA = 0.35,
sinA / cosA = TanA,
TanA = 0.35,
A = 19.3deg.
Fp = 24.5*sinA = Force parallel with plane.
Fv = 24.5*cosA = Force perpendicular to
plane.
uFv = 0.35Fv = Force of friction.
Fp - 0.35Fv = ma,
a = 0(block at rest),
Fp -0.35Fv = 0,
Fp = 0.35Fv,
24.5*sinA = 0.35*24.5*cosA,
Divide both sides by 24.5:
sinA = 0.35*cosA
Divide both sides by cosA:
sinA / cosA = 0.35,
sinA / cosA = TanA,
TanA = 0.35,
A = 19.3deg.
Answered by
abdirahman
answer
Answered by
kleopas
show me the steps on the calculation to the final answer
Answered by
Alphas
Meaning of fv,fp
Answered by
Alphas
Fp and fv their meanings