weight component down slope = m g sin 28.3
weight component normal to surface = m g cos 28.3
so friction force up slope = μ m g cos 28.3
so
162 + m g sin 28.3 = μ m g cos 28.3
A block of mass 57.1 kg rests on a slope having an angle of elevation of 28.3°. If pushing downhill on the block with a force just exceeding 162 N and parallel to the slope is sufficient to cause the block to start moving, find the coefficient of static friction.
HINT - Draw the block's free-body diagram and apply Newton's second law for the tilted x-component, solving for μs after substituting
fs, max = μsn.
1 answer
0 answers