Asked by shantrese
write the slope intercept equation for the line that pass through (-12,10) and is perpendicular to 4x+6y =3
Answers
Answered by
Damon
write
4x+6y =3
in slope intercept form
6 y = -4 x + 3
y = -(2/3)x + 1/2
slope m = -2/3
so slope of perpendicular = -1/m = 3/2
y = (3/2) x + b
10 = (3/2)(-12) + b
10 = -18 + b
b = 28
y = 3x/2 + 28
4x+6y =3
in slope intercept form
6 y = -4 x + 3
y = -(2/3)x + 1/2
slope m = -2/3
so slope of perpendicular = -1/m = 3/2
y = (3/2) x + b
10 = (3/2)(-12) + b
10 = -18 + b
b = 28
y = 3x/2 + 28