Asked by shantrese
                write the slope intercept equation for the line that pass through (-12,10) and is perpendicular to 4x+6y =3
            
            
        Answers
                    Answered by
            Damon
            
    write
4x+6y =3
in slope intercept form
6 y = -4 x + 3
y = -(2/3)x + 1/2
slope m = -2/3
so slope of perpendicular = -1/m = 3/2
y = (3/2) x + b
10 = (3/2)(-12) + b
10 = -18 + b
b = 28
y = 3x/2 + 28
    
4x+6y =3
in slope intercept form
6 y = -4 x + 3
y = -(2/3)x + 1/2
slope m = -2/3
so slope of perpendicular = -1/m = 3/2
y = (3/2) x + b
10 = (3/2)(-12) + b
10 = -18 + b
b = 28
y = 3x/2 + 28
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