Asked by shantrese
write the slope intercept equation for the line that pass through (-12,10) and is perpendicular to 4x+6y =3
Answers
Answered by
Damon
write
4x+6y =3
in slope intercept form
6 y = -4 x + 3
y = -(2/3)x + 1/2
slope m = -2/3
so slope of perpendicular = -1/m = 3/2
y = (3/2) x + b
10 = (3/2)(-12) + b
10 = -18 + b
b = 28
y = 3x/2 + 28
4x+6y =3
in slope intercept form
6 y = -4 x + 3
y = -(2/3)x + 1/2
slope m = -2/3
so slope of perpendicular = -1/m = 3/2
y = (3/2) x + b
10 = (3/2)(-12) + b
10 = -18 + b
b = 28
y = 3x/2 + 28
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.