Asked by Lisa
Write the slope intercept equation for the line that passes through (14,-2) and is perpendicular to 7x-10y=18
Answers
Answered by
Damon
y = m x + b
to get slope first find slope of given line
10 y = 7 x - 18
y = 0.7 x - 1.8
so slope of given line is 7/10
so slope of our line m = -10/7
so our line is
y = -10 x/7 + b
now find b from given point
-2 = -10*14/7 + b
-2 = -20 + b
b = 18
so
y = (-10/7) x + 18
to get slope first find slope of given line
10 y = 7 x - 18
y = 0.7 x - 1.8
so slope of given line is 7/10
so slope of our line m = -10/7
so our line is
y = -10 x/7 + b
now find b from given point
-2 = -10*14/7 + b
-2 = -20 + b
b = 18
so
y = (-10/7) x + 18
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