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current is 9/60 amps
power= I^2 r= (9/60)^2*10
power= I^2 r= (9/60)^2*10
To find the current, you can use Ohm's Law, which states that V = I * R, where V is the voltage and R is the resistance.
In this case, the voltage is 9 volts, and the total resistance is the sum of all the resistors in series: 10 ohms + 20 ohms + 30 ohms = 60 ohms.
Using Ohm's Law, you can calculate the current:
I = V / R = 9V / 60Ω = 0.15 A
Now that you have the current, you can calculate the power absorbed by the 10-ohm resistor:
P = I^2 * R = (0.15 A)^2 * 10Ω = 0.0225 * 10 W = 0.225 W
Therefore, the power absorbed by the 10-ohm resistor is 0.225 watts.