Asked by Kate
Find the limit as x->0 of (2-2cos(x))/(sin(5x))
Mathematically I got 2/5, but on the graph it appears to be 0.
Mathematically I got 2/5, but on the graph it appears to be 0.
Answers
Answered by
MathMate
Not sure how you got 2/5, but I got 0 as well.
Here's what I did:
Lim x->0 (2-2cos(x))/sin(5x)
both numerator and denominator evaluate to zero, so we can use d'Hôpital's rule:
=Lim x->0 (0+2sin(x))/5cos(5x)
This new expression evaluates to 0/5=0, which is therefore the answer.
Here's what I did:
Lim x->0 (2-2cos(x))/sin(5x)
both numerator and denominator evaluate to zero, so we can use d'Hôpital's rule:
=Lim x->0 (0+2sin(x))/5cos(5x)
This new expression evaluates to 0/5=0, which is therefore the answer.
Answered by
Kate
Thanks. I made a really stupid error. You've been very helpful in answering my calc questions. I really appreciate it.
Answered by
MathMate
You're very welcome.
Keep up the good work. Calculus is best learned with lots of practice.
Keep up the good work. Calculus is best learned with lots of practice.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.