You need Ka (dissociation constant) for
CH3COOH.
calculate pH of 0.1M CH3COOH of 100ml of that solution?
4 answers
then what must i do after i have the Ka of CH3COOH
Ka*[CH3COOH]/[A-]=[H3O+]
pH=-log[H3O+]
that's it :)
pH=-log[H3O+]
that's it :)
6.99