Question
What is the molarity of CH3COOH in vinegar containing 4.0% CH3COOH by mass and having a density of 1.02 g/ml?
Answers
DrBob222
density of 1.02 g/mL x 1000 mL = 1020 g/L. grams CH3COOH in that 1000 mL is 1020 x 0.04 = 40.8 grams.
mols in that 40.8 g = 40.8/molar mass CH3COOH = ?
Since that is the mols/L then that is the molarity.
mols in that 40.8 g = 40.8/molar mass CH3COOH = ?
Since that is the mols/L then that is the molarity.