Asked by Catarina
A particle has an initial horizontal velocity of 1.8 m/s and an initial upward velocity of 4.7 m/s. It is then given a horizontal acceleration of 2.3 m/s2 and a downward acceleration of 1.6 m/s2.
What is its speed after 1.9 s?
Answer in units of m/s.
What is the direction of its velocity at this time with respect to the horizontal?
Answer between −180 degrees and +180 degrees.
Answer in units of degrees.
What is its speed after 1.9 s?
Answer in units of m/s.
What is the direction of its velocity at this time with respect to the horizontal?
Answer between −180 degrees and +180 degrees.
Answer in units of degrees.
Answers
Answered by
drwls
2.3*t gets added to the initial horizontal velocity component (1.8)
1.6*t gets subtracted from the initial vertical velocity component (+4.7).
Compute the resulting velocity components at t = 1.9s, and then compute the magnitude(speed)using the Pythagorean theorem.
The ratio of the velocity components. Vy/Vx, is the tangent of the angle they are asking for.
1.6*t gets subtracted from the initial vertical velocity component (+4.7).
Compute the resulting velocity components at t = 1.9s, and then compute the magnitude(speed)using the Pythagorean theorem.
The ratio of the velocity components. Vy/Vx, is the tangent of the angle they are asking for.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.