Question

A particle's initial velocity is given by vox = -1.0 m/s and voy = 3.0 m/s. Its acceleration is ax = 0.50 m/s^2 and ay = -0.90 m/s^2 (a) Calculate its velocity 2.0 s later. (b) Calculate its displacement at that time.

Answer 1

I will be happy to critique your thinking.

Answer 2

Solve for velocity at 2.0s
vx = v0x + axt
vx = (-1m/s) + (0.5m/s2)(2.0s)
vx = 0m/s

vy = v0y + ayt
vx = (3m/s) + (-0.9m/s2)(2.0s)
vx = 1.2m/s

v = 0m/s(x hat) + 1.2m/s(y hat)

Calculate displacement.
∆x = v0xt + 1/2axt2
∆x = (-1m/s)(2.0s) + 1/2(0.5m/s2)(2.0s)2
∆x = -1m

∆y = v0xt + 1/2axt2
∆y = (3m/s)(2.0s) + 1/2(-0.9m/s2)(2.0s)2
∆y = 4.2m

y = -1.0m(x hat) + 4.2m(y hat)