Asked by Melissa
Calculate the molar solubility of MgF2 in 0.08M MgCl2 at 25 degrees C.
Answers
Answered by
DrBob222
MgF2 ==> Mg^+2 + 2F^-
Ksp = (Mg^+2)(F^-)^2
Substitute 0.08 M for (Mg^+2) and solve for (F^-).
Ksp = (Mg^+2)(F^-)^2
Substitute 0.08 M for (Mg^+2) and solve for (F^-).
Answered by
Melissa
do I use the Ksp of MfF2 and plug it in the equation?
Answered by
DrBob222
Yes.
Answered by
James
from the equation:
Ksp=(.08M)(F^-)^2
there are two unknown how do we solve it
Ksp=(.08M)(F^-)^2
there are two unknown how do we solve it
Answered by
laurie
you have to find the Ksp in the back of your chemistry book.
Answered by
Matt
the value 3.0x10^-5 was wrong for me?
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