A moving electron passes near the nucleus of a gold atom, which contains 79 protons and 118 neutrons. At a particular moment the electron is a distance of 7.5 × 10−9 m from the gold nucleus.

Question

What is the magnitude of the force exerted by the gold nucleus on the electron?

Answer 1

I seem to recall answering this already.

F = k*Q1*Q2/R^2 = 79k*e^2/R^2

(Coulomb's law; k = Coulomb's constant)

Get to know it

Answer 2

I'm not getting the answer using this formula. Can you explain it a little more. Thanks