Question
A 1.60-kg bottle of vintage wine is lying horizontally in a rack. The two surfaces on which the bottle rests are 90.0° apart, and the right surface makes an angle of 45.0° with respect to the horizontal. Each surface exerts a force on the bottle that is perpendicular to the surface. Both forces have the same magnitude F. Find the value of F. Assume g = 9.81 m/s2.
Answers
aprilann
F1=F2
F1= Fn*sin45
= (1.60kg x 9.81 m/s^2) * sin45
= 11.10 N
F1= Fn*sin45
= (1.60kg x 9.81 m/s^2) * sin45
= 11.10 N