Asked by Anonymous

Walking at 4km/h, Bruce can make the roundtrip between his campsite and Lookout Point in 2.5 h. Rowing on Crooked River, he can row upstream from the campsite to Lookout Point in 1 h and can row back again in 40 min. Find Bruce’s rate of rowing in still water and the speed of the current in Crooked River.........I know how to solve i would really apreciate it if someone can give me the 2 equations.

Answered by Reiny
The first sentence just tells you that the roundtrip is 4(2.5) or 10 km, so each way is 5 km

let his rate of rowing in still waters be x km/h
let the rate of the current be x km/h
time to go with the current = 5/(x+y) = 1
or x+y = 5
time to go against the current = 5/(x-y) = 2/3
or 2x-2y = 15

There are your two equations.
You said you knew how to solve them, let me know what you got
Answered by Anonymous
rate of rowing= 6.25
i don't think my solution is correct though...
Answered by Reiny
Sorry, I had my equations backwards.
Clearly the time has to be less for a faster speed

so 5/(x+y) = 2/3 --->2x+2y = 15
and 5/(x-y) = 1 ----> x-y= 5

You still get x = 6.25, but y is now 1.25
whereas before it would have been negative.
Good for you to doubt the result.
Answered by Anonymous
Thank You So MUCH!!!
Answered by Makenna Chung
why did you do 2x and 2y?
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