Asked by Anonymous

the work function for metallic Caesium is 2.14 eV. Calculate the kinetic energy and the speed of the electrons ejected by light of wavelength 700 nm
Answered by drwls
The photon energy is h*c/(wavelength) = 2.84*10^-19 J = 1.77 eV

Unless I made an error somewhere, there is not enough energy in a photon of that wavelength to eject a photoelectron.
Answered by zako
2.8397j
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