1. The work function of electrons from gold is 4.76 eV. Determine the red border of the photoelectric effect for gold.

1 answer

The red border of the photoelectric effect is the minimum frequency of light required to eject electrons from a metal surface. This can be calculated using the equation:

E = hf

Where:
E = energy of the photon (red border)
h = Planck's constant = 4.1357 x 10^-15 eV·s
f = frequency of the photon

To determine the red border, we need to convert the work function from electron volts (eV) to joules:

4.76 eV * 1.602 x 10^-19 J/eV = 7.62 x 10^-19 J

Now we can use this energy to calculate the frequency of the photon:

7.62 x 10^-19 J = (4.1357 x 10^-15 eV·s) * f
f = 1.84 x 10^14 Hz

Therefore, the red border of the photoelectric effect for gold is approximately 1.84 x 10^14 Hz.
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