Question
hi
can you please help me with this particular question?
thanks a lot
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The work function of a material refers to the minimum energy required to remove an electron from the material. Assume that the work function of gold is 4.90eV and that of cesium is 1.90eV. Calculate the maximum wavelength of light for the photoeclectric emission of electrons for gold and cesium.
h c/(min. wavelength) = e*(work function)
Solve for the minimum wavelength.
h is Planck's constant
Convert the work function (in volts) to energy units by multiplying by the electron charge, e.
can you please help me with this particular question?
thanks a lot
___________________________________
The work function of a material refers to the minimum energy required to remove an electron from the material. Assume that the work function of gold is 4.90eV and that of cesium is 1.90eV. Calculate the maximum wavelength of light for the photoeclectric emission of electrons for gold and cesium.
h c/(min. wavelength) = e*(work function)
Solve for the minimum wavelength.
h is Planck's constant
Convert the work function (in volts) to energy units by multiplying by the electron charge, e.
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