Asked by skhan
a .415 kg baseball is pitched at 42 m/s. the batter hits it horizontally to the pitcher at 58 m/s.
a) find the change in momentum of the ball.
b) if the ball and bat were in contact for 4.6*10^-4 s what would be the average force while they touched?
a) find the change in momentum of the ball.
b) if the ball and bat were in contact for 4.6*10^-4 s what would be the average force while they touched?
Answers
Answered by
bobpursley
changemomentum=mass*changevelocty=
= mass*(vf-vi)=mass(-58-42)
force*time=change of momentum
= mass*(vf-vi)=mass(-58-42)
force*time=change of momentum
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