Asked by n
A 0.20 kg baseball is pitched horizontally with a speed of + 40 m/s. When it hits the bat a force of 1.7x10^4 N acts on the ball to send it soaring in the opposite direction. If the bat and ball are in contact for 8.0x10^-3 s, what is the impulse delivered to the ball by the bat?
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Answered by
Anonymous
Force * time = change of momentum = impulse
1.4*10^7 * 8 * 10^-3 = impulse
Is there no part b where they ask you the resulting speed ?
1.4*10^7 * 8 * 10^-3 = impulse
Is there no part b where they ask you the resulting speed ?
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