Asked by Ray Scholz

You're on planet YZ and an astronaut observes that a 1.0 m long pendulum has a period of 1.50s. What is the free-fall accerlerttion on YZ? I know the answer is 17.6 because I worked it backwards but if the answer was given, I wouldn't know how to change the variables around-that's what I need help with

Answers:
1.003 m/s^2
26.4 m/s^2
17.6 m/s^2
0.23 m/s^2

Could someone direct me how to set this up or give me any assistance, please?
Answered by Ray Scholz
Never mind-Iot it-just as I typed this in and submitted it
Thank you
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