Question
You're on planet YZ and an astronaut observes that a 1.0 m long pendulum has a period of 1.50s. What is the free-fall accerlerttion on YZ?
Answers:
1.003 m/s^2
26.4 m/s^2
17.6 m/s^2
0.23 m/s^2
Could someone direct me how to set this up or give me any assistance, please?
Answers:
1.003 m/s^2
26.4 m/s^2
17.6 m/s^2
0.23 m/s^2
Could someone direct me how to set this up or give me any assistance, please?
Answers
Henry
T^2 = 4*(3.142)^2*(L/g) = 2.25
39.48(1/g) = 2.25,
39.48/g = 2.25,
g = 39.48 / 2.25 = 17.6m/s^2.
39.48(1/g) = 2.25,
39.48/g = 2.25,
g = 39.48 / 2.25 = 17.6m/s^2.