Question
How do you write a redox reaction in an acidic environment for this?
Cu^+2 + I- => CuI + I2
I understand that you get these equations for redox, but how do you put them in an acidic environment when there are no oxygens in the equation?
2I- => I2 + 1 electron
1 electron + Cu^+2 => CuI
Cu^+2 + I- => CuI + I2
I understand that you get these equations for redox, but how do you put them in an acidic environment when there are no oxygens in the equation?
2I- => I2 + 1 electron
1 electron + Cu^+2 => CuI