Asked by Annie
Please write down the redox reactions (using the half-reaction method!)
a)Cl2 from OCl- and Cl- in acidic solution
b)Br2 from BrO3- and Br- in acidic solution
-You don't have to do both, but could you help me step up the half reactions especially for OCl- --> Cl2
a)Cl2 from OCl- and Cl- in acidic solution
b)Br2 from BrO3- and Br- in acidic solution
-You don't have to do both, but could you help me step up the half reactions especially for OCl- --> Cl2
Answers
Answered by
DrBob222
2 OCl^- + 2e + 4H^+ ==> Cl2 + 2H2O
2Cl^- ==> Cl2 + 2e
When you add these two you end up with twice the coefficients so divide everything by 2. I do it this way because it's easier to explain to students and then divide by 2; however, you can do it from the beginning by
OCl^- + e + 2H^+ ==> Cl + H2O
Cl^- ==> Cl + e
but students don't like to see atomic Cl because they always write it as Cl2. However, when you add the second equation 1 to the second equation 2 you end up with a Cl on the right with another Cl on the right and that makes Cl2.
2Cl^- ==> Cl2 + 2e
When you add these two you end up with twice the coefficients so divide everything by 2. I do it this way because it's easier to explain to students and then divide by 2; however, you can do it from the beginning by
OCl^- + e + 2H^+ ==> Cl + H2O
Cl^- ==> Cl + e
but students don't like to see atomic Cl because they always write it as Cl2. However, when you add the second equation 1 to the second equation 2 you end up with a Cl on the right with another Cl on the right and that makes Cl2.
Answered by
Annie
Thank you so much! I understand now.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.