Asked by kelly
A charge of +q is placed at y = 0 m. Another charge of +2q (twice the other charge) is placed at y = +6.52 meters. Where on the y axis is the total electric field zero?
Answers
Answered by
drwls
Somewhere on the y axis between the two charges there E fields due to each particle are equal and opposite. Use Coulomb's law to fnd that location.
q/y^2 = 2q/(6.52 - y)^2
Solve for y
q/y^2 = 2q/(6.52 - y)^2
Solve for y
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