Asked by eddie
the diagonals of a rectangle are 8 units long and intersect at a 60 degree angle. Find the dimensions of the rectangle?
Answers
Answered by
Reiny
The diagonals bisect each other, so each segment is 4 units
If they form a 60° angle, then it must be an equilateral triangle and the width of the rectangle is 4 units
let the base be b
b^2 + 4^2 = 8^2
b^2 = 64-16 = 48
b = √48 = 4√3
rectangle is 4√3 by 4
If they form a 60° angle, then it must be an equilateral triangle and the width of the rectangle is 4 units
let the base be b
b^2 + 4^2 = 8^2
b^2 = 64-16 = 48
b = √48 = 4√3
rectangle is 4√3 by 4
Answered by
Ally jane
The diagonals of a rectangle are 16 units long and intersect at a 60 degree angle. Find the dimensions of the rectangle.
Answered by
Paco
Area of a rectangle 18m long that intersect at a 60 degree angles
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