Asked by Kristen
A Corvette, initially traveling at a speed of 6 m/s, speeds up (accelerates) at a rate of 0.2 m/s2 for 3 s. How far does it travel during that time?
I tried d=vi*t-.2*t^2 but I did not get the correct answer
I tried d=vi*t-.2*t^2 but I did not get the correct answer
Answers
Answered by
drwls
You should have used the equation
d = vi*t + 0.1*t^2
You don't have an minus sign in front of the accleration term, and you forgot to divide the acceleration by 2.
d = vi*t + 0.1*t^2
You don't have an minus sign in front of the accleration term, and you forgot to divide the acceleration by 2.
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