A manufacturer of light bulbs knows that 3% of the production of their 60W bulbs will be defective. What is the probability that exactly 5 bulbs in a carton of 144 will ne defective?

Answer 1

(0.03)^5*(0.97)^139*144!/(139!*5!)
= 2.43*10^-8*1.45*10^2*5.77*10^1/120
= 0.169