Asked by andrea
An object is thrown up at an angle of 40.0 degree above the horizontal and reaches a maximum height H.
If the angle is now doubled to 80.0^degree, but nothing else is changed, its maximum height will be
a. 1.67 H.
b. 2.00 H.
c. 2.35 H.
d. 4.00 H.
If the angle is now doubled to 80.0^degree, but nothing else is changed, its maximum height will be
a. 1.67 H.
b. 2.00 H.
c. 2.35 H.
d. 4.00 H.
Answers
Answered by
drwls
The maximum height reached is proportional to (V^2/g) sin^2 theta
V and g do not change.
Calculate the ratio (sin80/sin40)^2
That, times H, will be the answer.
V and g do not change.
Calculate the ratio (sin80/sin40)^2
That, times H, will be the answer.
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