Asked by Anonymous
If an object is thrown in an upward direction from the top of a building 160 ft. high at an initial speed of 21.82 mi/h., what is its final speed when it hits the ground?(Disregard wind resistance. Round answer according to significant figures and do not reflect negative direction in your answer.
Answers
Answered by
drwls
Kinetic energy increase = Potential energy decrease
(M/2) [V2^2 - V1^2] = M g H
[V2^2 - V1^2] = 2 g H
Solve for V2, the final velocity.
V1 = 21.82 m/s
The V2 answer will not depend upon the direction it was thrown!
(M/2) [V2^2 - V1^2] = M g H
[V2^2 - V1^2] = 2 g H
Solve for V2, the final velocity.
V1 = 21.82 m/s
The V2 answer will not depend upon the direction it was thrown!
Answered by
David
the answer you gave is very incorrect according to the answer choices given
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