Asked by andrea
A cannonball is fired horizontally from a 240 {m}-high cliff toward a vertical building 720 {m} away with an initial velocity of 120 {m/s}.
When the ball will hit the building?
in
a. 7.00 {s}
b. 6.00 {s}
c. less than 6.00 {s}
d. more than 7.00 {s}
When the ball will hit the building?
in
a. 7.00 {s}
b. 6.00 {s}
c. less than 6.00 {s}
d. more than 7.00 {s}
Answers
Answered by
drwls
The ball would take sqrt(2H/g) = 7.00 s to hit the ground, but will reach the building in 720/120 = 6.00 s
So it will not hit the ground first, and will arrive in exactly 6.00 s.
So it will not hit the ground first, and will arrive in exactly 6.00 s.
Answered by
marrtissey
y=h=120m t=d/v y=1/2 g t^2 t=√(240/9.80s^2 ) t=440m/(110 m/s) t^2=2y/g
x=d=440m t=4s t=√(2y/g)
V_0=110 m/s 4s. to hit the building t=√((2(120m))/(9.80 m/s^2 ))
t=√(24.5s^2 )
t= ? To hit the ground in t=4.95s
x=d=440m t=4s t=√(2y/g)
V_0=110 m/s 4s. to hit the building t=√((2(120m))/(9.80 m/s^2 ))
t=√(24.5s^2 )
t= ? To hit the ground in t=4.95s
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