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marrtissey
Answers (2)
y=h=120m t=d/v y=1/2 g t^2 t=√(240/9.80s^2 ) t=440m/(110 m/s) t^2=2y/g x=d=440m t=4s t=√(2y/g) V_0=110 m/s 4s. to hit the building t=√((2(120m))/(9.80 m/s^2 )) t=√(24.5s^2 ) t= ? To hit the ground in t=4.95s
x = 1/2 a t^2 ==> a = (2x) / t^2 a = 2(11.26m) / (3.17s)^2 a = 22.52m / 10.0489s^2 = 2.241041308 ==> sig figs a = 2.24m/s^2