Asked by Ashley
The answer is 50.0 torr and I got 46.0 torr but idk what I did wrong.
Find the vapor pressure of a solution of 164 g of C3H8O3 and 338 mL of water at 39.8 degrees Celsius. Water's VP at 39.8 degrees celsius is 54.74 torr; it's density is 0.992 g/mL.
Find the vapor pressure of a solution of 164 g of C3H8O3 and 338 mL of water at 39.8 degrees Celsius. Water's VP at 39.8 degrees celsius is 54.74 torr; it's density is 0.992 g/mL.
Answers
Answered by
DrBob222
If you had shown what you did we could tell you what you did wrong.
moles C3H8O3 = grams/molar mass
moles H2O = (338 mL*0.992 g/mL)/molar mass
mole fraction H2O = moles H2O/total moles.
vap pressure water = moles fraction H2O x normal vap pressure water. I get 49.96 in a quickie calculation which rounds to 50.0 torr. You should do it more accurately than I.
moles C3H8O3 = grams/molar mass
moles H2O = (338 mL*0.992 g/mL)/molar mass
mole fraction H2O = moles H2O/total moles.
vap pressure water = moles fraction H2O x normal vap pressure water. I get 49.96 in a quickie calculation which rounds to 50.0 torr. You should do it more accurately than I.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.