Asked by Sumaiya
The shaded face of the cuboid is a square and has an area of 64 cm2. What is the volume of the cuboid that has a width of 17 cm? Can you plzz explain how you found you're answer.....
-THANX♥
-THANX♥
Answers
Answered by
helper
If I am following your problem.
The area of ONE shaded face = 64 cm^2
Since, this face is a square, the length L equals the height h.
L = H
Cuboid SA = 2Lw + 2Lh + 2wh
Since you have the SA (surface area) of one face, and L = H,
SA = 2Lh
SA = 2LL (L = h)
64 = 2L^2
32 = L^2
L = (sqrt(32)) = 5.66 cm^2
Volume V = Lwh
L = 5.66
h = 5.66
w = 17
V = (5.66)(17)(5.66)
V = ?
You can finish this now.
I am not a tutor, but I think this is right.
The area of ONE shaded face = 64 cm^2
Since, this face is a square, the length L equals the height h.
L = H
Cuboid SA = 2Lw + 2Lh + 2wh
Since you have the SA (surface area) of one face, and L = H,
SA = 2Lh
SA = 2LL (L = h)
64 = 2L^2
32 = L^2
L = (sqrt(32)) = 5.66 cm^2
Volume V = Lwh
L = 5.66
h = 5.66
w = 17
V = (5.66)(17)(5.66)
V = ?
You can finish this now.
I am not a tutor, but I think this is right.
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