Asked by Krishnam Kumawat
A Cuboid with lenght as 6m and breadth as 3m, is floating in a lake. A man comes and sits on it and it sinks 1cm, then find the weight of the man. (Take g=10 m/s -2)
Answers
Answered by
bobpursley
weight of man=weight of water displaced
= 6*3*.01* density water* g
= .18m^3*1E3Kg/m^3*9,8 m/s^2
= .18*E3*9.8 Newtons
= 6*3*.01* density water* g
= .18m^3*1E3Kg/m^3*9,8 m/s^2
= .18*E3*9.8 Newtons
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