Asked by Anonymous 3
Let h be the function defined by the equation below.
h(x)= x^3-x^2+x+6
h(-8)
h(x)= x^3-x^2+x+6
h(-8)
Answers
Answered by
helper
This is calculus?
h(x)= x^3-x^2+x+6
h(-8)
Plug -8 in for x and do the math.
h(x)= x^3-x^2+x+6
h(-8)
Plug -8 in for x and do the math.
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