Asked by Brittany
lim as x --> infinity of (x^2-16)/(x-4) is 8
By graphing, find an interval for near zero such that the difference between your conjectured limit and the value of the function is less than 0.01. In other words, find a window of height 0.02 such that the graph exits the sides of the window and not the top or bottom. What is the window?
____≤ x ≤_________
____ ≤ y ≤ ________
I'm confused on how to find these intervals with the given 0.01 and 0.02. Thanks!
By graphing, find an interval for near zero such that the difference between your conjectured limit and the value of the function is less than 0.01. In other words, find a window of height 0.02 such that the graph exits the sides of the window and not the top or bottom. What is the window?
____≤ x ≤_________
____ ≤ y ≤ ________
I'm confused on how to find these intervals with the given 0.01 and 0.02. Thanks!
Answers
Answered by
Reiny
the limit of (x^2-16)/(x-4) as x --> infinity is infinity, not 8
lim (x^2-16)/(x-4) as x --> 4 is 8
= lim (x+4)(x-4)/(x-4) as x-->4
= lim x+4 as x --->4
= 4 + 4 = 8
lim (x^2-16)/(x-4) as x --> 4 is 8
= lim (x+4)(x-4)/(x-4) as x-->4
= lim x+4 as x --->4
= 4 + 4 = 8
Answered by
Josie
Sorry! That was a typo. It was as the limit approaches 4. I'm still confused on how to find the y intervals.
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