Asked by lauren
I'm working on solving and graphing inequalities. My problem is 1 < 6n + 3n
I solve to get 1/9 < n
When I graph and show my set, is it (1/9, infinity) or is it (0, infinity)?
I thought it would be (1/9, infinity), but my teacher showed (0, infinity).
On another one, it was 8 < 8x + 2x which solved to 4/5 < x and she showed the answer as (4/5, infinity) so I don't understand how one would be 0 and one would be 4/5.
Thank you
I solve to get 1/9 < n
When I graph and show my set, is it (1/9, infinity) or is it (0, infinity)?
I thought it would be (1/9, infinity), but my teacher showed (0, infinity).
On another one, it was 8 < 8x + 2x which solved to 4/5 < x and she showed the answer as (4/5, infinity) so I don't understand how one would be 0 and one would be 4/5.
Thank you
Answers
Answered by
Anonymous
It is 1/9 to infinity
The second one is fine.
I bet she thought 0 and not 1 was on the left side of the original inequality.
The second one is fine.
I bet she thought 0 and not 1 was on the left side of the original inequality.
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